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08/23/2004 4:43 PM ET
Detroit's Higginson takes Bank of America Presents the American League Player of the Week award
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Detroit Tigers outfielder Bobby Higginson, who led the League in slugging, on-base percentage and RBI, has been named Bank of America Presents the American League Player of the Week for the period ending August 22. Bank of America, the official bank of Major League Baseball, is the presenting sponsor of the American League and National League Player of the Week Awards, which reflect the bank's long-standing tradition of promoting and recognizing higher standards of accomplishment.

In five games last week, Higginson batted .556 (10-18) with a 1.278 slugging percentage, a .667 on-base percentage, six runs, a double, four home runs and 12 RBI. The veteran outfielder posted 10 RBI overall in a three-game series at Chicago's U.S. Cellular Field last week, including two multi-homer efforts. Those two games helped lift Detroit to 11-8 and 8-4 victories, respectively. He now has 15 multi-homer games in his career. This is Higginson's third career weekly award (he won twice in 2000).

Other contenders were Oakland's Erubiel Durazo (.478, 4 HR, 10 RBI); Boston's Jason Varitek (.474, 3 HR); Aaron Rowand (.545, AL-best 10 R) of the Chicago White Sox; Minnesota's Shannon Stewart (.520, AL-high 13 hits); Seattle's Ichiro Suzuki (AL-best .571); and Gary Sheffield (.435, 4 HR, 8 RBI) of the New York Yankees.

Pitchers on this week's ballot were Brad Radke (2-0, 0.64 ERA, 14.0 IP) of the Twins and Tampa Bay's Dewon Brazelton (2-0, 2.92 ERA). Radke has not lost since July 16, going 4-0 with three no-decisions in that span for AL Central-leading Minnesota.

Tourneau, the world's largest watch store, is proud to award the Bank of America Presents the American League Player of the Week winner Bobby Higginson with a Tourneau luxury Swiss timepiece from its Safari collection.

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